Afree falling object's motion can be describingby the velocity time graph shown approximately what is the objects position at 6.0 s. 1- 10m 2- 180m 3- 60m 4- 3600m

According to second equation of motion

S = Vi t + 1/2 at²         ( where Vi= initial velocity , t= time ,a= acceleration,)

Before starting the motion object is at rest so initial velocity =Vi = 0

As object  is falling freely so it posses

acceleration due to gravity = g =10 m/sec²    (a =g)

time =t= 6.0 s

Putting values of a=g ,, t and Vi in second equation of motion.

S= (0)(6.0s) + 1/2 (10m/s²) (6.0s)²

 = 0 + 1/2 ( 10m/s²)(36s²)

S  = 180m

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