Anegative charge, q1, of 6 µc is 0.002 m north of a positive charge, q2, of 3 µc. what is the magnitude and direction of the electrical force, fe, applied by q1 on q2? a) magnitude: 8 × 10^1 n direction: south b) magnitude: 8 × 10^1 n direction: north c) magnitude: 4 × 10^4 n direction: south d) magnitude: 4 × 10^4 n direction: north

D. magnitude: 4 × 104 N

direction: north

D) magnitude: 4 × 10^4 N

direction: north

Explanation:

q₁ = magnitude of negative charge = 6 x 10⁻⁶ C

q₂ = magnitude of positive charge = 3 x 10⁻⁶ C

r = distance between the two charges = 0.002 m

Magnitude of electric force between the two charges is given as

F = k q₁ q₂/r²

where k = constant = 9 x 10⁹

inserting the values

F = (9 x 10⁹) (6 x 10⁻⁶) (3 x 10⁻⁶)/(0.002)²

F = 4 x 10⁴ N

magnitude : 4 x 10⁴ N

Direction : North

we know that a negative charge pulls a positive charge towards it. the negative charge "q₁" is north of the positive charge. hence the charge q₁ apply force on charge q₂ in north direction.

this allows people to make the best decision or pursue the best option. when alternatives are weighed using their advantages and disadvantages, the option whose disadvantages outweigh the advantages (based on a qualitative or quantitative analysis) are shunned while those whose advantages outweigh their disadvantages are pursued.  

work: w = fd (given)

work done by chet   =50*1 = 50 j

work done by mika =40*2 = 80 j

work done by sara =30*1.5 = 45 j

work done by bill =60*0.5 = 30 j

students in order from the greatest amount of work done to the least is mika> chet> sara> bill

hence option (b) is correct.