When you drop a 0.37kg apple earth exerts a force on it that accelerates it at 9.8m/s^2 toward the earths surface. according to newtons third law, the apple must exert an equal but opposite force on earth.

force applied due to earth on the apple is given as

given that

m = 0.37 kg

a = 9.8 m/s^2

now we have

now as per Newton's III law equal and opposite force is applied on earth

so now we can find acceleration of Earth using same equation as we used above

here we know that

m = mass of earth

F = 3.63 N

so acceleration of earth is very small and given by above value

c.the charges if the proton and electron and gravity

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