If you seal a container of air at room temperature (20.0 degrees celcius) and then put it in the refrigerator (2.00 degrees celcius) what will the pressure inside the container be? assume atmospheric pressure equal to 100,000 pa.

The value of pressure inside the container when it is sealed at room temperature and then put in the refrigerator is 93860 Pa.

Amounts law or Gay Lussac's law is the law used to show the relationship between the pressure and the temperature of the gases.

According to this law, when the volume of the gas is constant, the pressure of the given sum of the gas is directly proportional to the temperature of the gas. By this law,

Here, (subscript 1,and 2) is used for the initial and final amount of pressure and temperature.

The initial temperature is 20 degrees Celsius and the final temperature is 2 degrees Celsius. Convert it into the kelvin by adding 273.15.

The atmospheric pressure is equal to 100,000 Pa. Put the values in the above expression as,

Thus, the value of pressure inside the container when it is sealed at room temperature and then put in the refrigerator is 93860 Pa.

Learn more about the gas law here;

The pressure inside the container will be 9.39×10⁴Pa

At constant volume, the pressure in a container is directly proportional to its absolute temperature.

If air in a container is sealed at 20⁰C at a pressure equal to the atmospheric pressure and cooled to 2.00⁰C, the pressure inside the container falls.

Convert the temperature in Celsius to Kelvin.

Use the expression for the pressure law.

Substitute 100,000 Pa for P₁, 293.16 K for T₁ and 275.15K for T₂.

The pressure in the container (correct to 2 sf) is 9.39×10⁴Pa

at right angles to each other

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