Acar with a mass of 1.2 x 10^3 kilograms starts from rest and attains a speed of 20 meters/seconds in 5 seconds. what net force acted on the car to cause that acceleration? a.) 3.0 x 10^2 newton’s b.) 6.0 x 10^2 newton’s c.) 1.2 x 10^3 newton’s d.) 4.8 x 10^3 newton’s e.) 1.2 x 10^4 newton’s

The mass of the car [m] = 1.2×10^3 kg.

The initial speed of car[u]= 0 m/s

The final speed of car [v]= 20 m/s

We are asked to calculate the force required to increase the speed from 0 to 20 m/s.

The momentum of a substance is defined as product of mass and velocity.

Mathematically momentum p=m×v   [Here m is the mass]

From Newton's second law we know that-

                            [here t is the time]

                                   [ANS]

Hence the correct answer to the question is C.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards