An asteroid is traveling in a straight line at a constant speed of 327 m/s. how long will it take for a displacement of 732 km to occur?

Answer

2,238.53 seconds

Explanation

For  a constant speed, to get the time taken to travel for a certain distance we use the formula;

speed = displacement/time

∴ time = displacement/speed

           = (732 Km) / (327 m/s)

732 Km = (732×1000) m

              = 732000 m

∴ Time  = 732000/327

              = 2,238.53 seconds

Time = 2238.53 s

Given data:

Speed of the asteroid = 327 m/s

Displacement = 732 Km

Time = ?

Solution:

Displacement = 732 Km = 732000 m

As we know:

Speed = Displacement/time

Time = Displacement/speed

Putting values in above formula:

Time = 732000 m/327

Time = 2238.53 s

So asteroid will take 2238.53 seconds to travel 732 km.

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the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s