Apoint charge of 6.8 c moves at 6.5 × 104 m/s at an angle of 15° to a magnetic field that has a field strength of 1.4 t. what is the magnitude of the magnetic force acting on the charge? a) 1.6 × 10–1 n b) 6.0 × 10–1 n c) 1.6 × 105 n d) 6.0 × 105 n

As per the question, the point charge is given as [q] = 6.8 C

The velocity of the charged particle [v] =

The magnetic field [B] = 1.4 T

The angle made between magnetic field and velocity = 15 degree.

We are asked to calculate the magnetic force experienced by the charged  particle.

The magnetic force experienced by the charged particle is calculated as -

Magnetic force

                        i.e F = 

Hence, the force experienced by the charged particle is C i.e

when heated, the valance electrons increased their speed and transferred the heat from electron to electron.   i just took the test.

friction

explanation:

they us to move forward and backwards