Physics, 03.07.2019 06:00 monij4

Amass of 0.273 kg is placed on an incline of 38.382 degrees. it is attached by a rope over a pulley to a mass of 0.254 kg. find the coefficient of friction and the force of friction

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Answer from: neariah24

here tension in the string is counter balanced by weight of block of mass m1

so we can say

T = m_1g

$T = 0.254 \times 9.8 = 2.49 N$

now on the other side the block which is placed on the inclined plane

we can say that component of weight of the block and friction force is counter balanced by tension force

$m_2g sin\theta + F_f = T$

now we can plug in all values to find the friction force

$0.273 \times 9.8 sin38.382 + F_f = 2.49$

1.66 + F_f = 2.49

F_f = 0.83 N

so it will have 0.83 N force on it due to friction

now to find the friction coefficient

$F_f = \mu \times F_n$

here we know that

$F_n = m_2gcos\theta$

$F_n = 0.273 \times 9.8 \times cos38.382 = 2.1 N$

now from above equation

$0.83 = \mu \times 2.1$

$\mu = 0.38$

so friction coefficient will be 0.38

Answer from: Quest

Julia would be observing a. static electricity was caused by her sweater rubbing against her shirt and transferring electrons. she didn't touch anything metal, so that would cancel out b.she most likely didn't rub her sweater against her hair either, so that cancels out c.she also didn't scoot across the carpet while trying to take her sweater off, that cancels out d.so that leaves a.a. is correct.

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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Amass of 0.273 kg is placed on an incline of 38.382 degrees. it is attached by a rope over a pulley...

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