Consider horizontal parallel plates with a fixed potential difference. the upper plate has a voltage difference of 30 v with the lower plate, and they are separated by 3 cm. you move the two plates carefully to a separation of 4 cm. what is the strength of the electric field between the plates?

relation between potential difference and electric field is given as

so here we know that

d = 3 cm

So now when plates are separated to 4 cm distance carefully

the potential difference between them will change but the electric field between them will remain constant

So at distance of 4 cm also the electric field will be E = 1000 N/C

answer would be d.) i hope this

explanation:

would be false hope this out