A10 kg lawn mower is pushed along by a force applied at a 20 degree angle to the horizontal. if a the mower accelerates at 3.4 m/s^2, what is this force?

m = mass of lawn mower = 10 kg

a = acceleration along X-direction = 3.4 m/s²

let the applied force be "F"

from the force diagram , we see that only "F Cos20 " is acting along the horizontal direction .

hence F' = net force along x-direction = F Cos20

net force along x-direction is given as

F' = ma

F Cos20 = ma

inserting the values

F Cos20 = 10 x 3.4

F Cos20 = 34

F = 36.2 N

hence the force applied is 36.2 N  

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