If a 2 kg ball is at the edge of a 40 meter cliff and falls off, how much kinetic energy will the ball have when it hits the ground?

m = mass of the ball at the edge of the cliff = 2 kg

h = height of the cliff from where the ball falls off = 40 m

g = acceleration due to gravity = 9.8 m/s²

gravitational potential energy of the ball at the top of the cliff is given as

PE = mgh

inserting the above values in the formula

PE = (2) (9.8) (40)

PE = 784 J

KE = kinetic energy of the ball as hits the ground.

initially at the top of cliff , the ball has no kinetic energy and only potential energy. as the ball falls down the cliff , the speed of ball increase which increases the kinetic energy and potential energy decrease by same amount as the height above the ground decrease.

using conservation of energy

kinetic energy of ball as it hits the ground = Potential energy of the ball at the top of cliff

KE = PE

KE = 784 J

this is a good question! i'll do some research and come back when i have the answer!