A1,800 kg car is parked on a road that has an elevation level of 7°. suppose the coefficient of static friction is .65. what is the force of static friction?

m = mass of the car = 1800 kg

g = acceleration due to gravity = 9.8 m/s²

= force of gravity on the car

force of gravity on the car is given as

= mg

inserting the values

= (1800) (9.8) = 17640 N

= static frictional force acting on the car

from the force diagram of the car  , the static frictional force is opposite to the parallel component of force of gravity on the car . hence static frictional force mus balance the component of force of gravity parallel to incline surface.

hence

= Sin7

= (17640) Sin7

= 2149.8 N

probably not if net force is zero

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia