Aball rolls with a speed of 2.0m/s across a level table that is 1.0m above the floor. upon reaching the edge of the table it follows a parabolic path to the floor. how far along the floor is the landing spot from the table?

The distance covered by the ball is 0.9 m.

Explanation:

Given that,

Speed of ball = 2.0 m/s

Distance = 1.0 m

We need to calculate the time

Using equation of motion

Here, u = initial velocity=0

Where, h = distance

g = acceleration due to gravity

t = time

Put the value into the formula

We need to calculate the distance of the ball

Using formula of velocity

Hence, The distance covered by the ball is 0.9 m.

b

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.