The acceleration of a freely falling body is about 10m/sec/sec. if the ball is dropped from the top of a building what would its velocity be after 2 seconds?

The velocity will be 20 meters per second

The final velocity will be 20 m/s

According to first law of motion

Vf = Vi + at

Here we are given with

Vf = ?

Vi = 0  because it started from 0

a = 10 m/s²

t = 2 sec

So putting the values in the equation we get

Vf = 0 + 10 x 2

Vf = 20

So velocity after 2 seconds will be 20 m/s

the answer would be 32*f

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s