A57 kg boy and a 37 kg girl use a elastic rope while engaging in a tug-of-war on a frictionless icy surface. if the acceleration of the girl toward the boy is 3.2 m/s^2, determine the magnitude of the acceleration of the boy towards the girl.

The boy's acceleration toward the girl is 2.08 m/s^2.

Explanation:

According the Newton's Third Law, the force causing the girl accelerate towards the boy will be me with equal counter-force causing the boy to accelerate towards the girl. These forces will be of equal magnitude and allows us to determine the boy's acceleration:

The boy's acceleration toward the girl is 2.08 m/s^2.

3

step-by-step explanation:

10 - 2.8 = 7.2

2 2/5 = 2.4

7.2 / 2.4 = 3

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