An object travels in circular motion with a speed of 11.40 m/s. what is the centripetal acceleration if the radius of the circle is 5.52 m?

v = speed of the object moving in circle = 11.40 m/s

r = radius of the circle in which the object move = 5.52 m

a = centripetal acceleration of the object moving in circle

centripetal acceleration is given as

a = v²/r

where a = centripetal acceleration

v = linear speed of the object

r = radius of the circle

inserting the values

a = (11.40)²/5.52

a = 129.96/5.52

a = 23.5 m/s²

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever