A2 kilogram object falls a distance of 5 meters. how much potential energy does this object have before it falls? how much work is done on it by gravity as it falls

Given:

Mass of object, m = 2 kg

Distance, h = 5 m

To determine:

The potential energy and work done

Explanation:

Step 1: The potential energy of the object is given as:

PE = mgh

m = mass of the object, g = acceleration due to gravity = 9.8 m/s2; h = height

PE = 2 kg * 9.8 ms-2 * 5 m = 98 kgm²s⁻² = 98 J

Step 2: The work done by gravity can be expressed as:

W = Force * distance = F*h

F = mg = 2 * 9.8 = 19.6 N

W = 19.6 * 5 = 98 J

Ans: The potential energy and work done = 98 J

answer: the correct answer for the fill in the blank is rods.

rods are the specialized photoreceptor cells that are present in the retina of human eye. they are responsible for vision in the night time ( also called scotopic vision). they have very low visual acuity and color distinguishing ability.

as they are responsible for vision in night time, therefore they are found predominantly in the nocturnal animals.