Abowling bowl is thrown off the top of a building. determine distance the ball has fallen after falling for 3.0 s. remember, the gravitational acceleration (g) is 9.8 m/s2. (hint: d = ½gt2)

d = distance the bowling ball has fallen = ?

g = acceleration due to gravity acting on the ball by earth = 9.8 m/s²

t = time of fall for the ball = 3.0 s

distance the ball has fallen is given as

d = (0.5) g t²

inserting the above values in the equation above

d = (0.5) (9.8 m/s²) (3.0 s)²

d = (0.5) (9.8 m/s²) (9.0 s²)

d = (4.9 m/s²) (9.0 s²)

d = 44.1 m

hence the distance fallen by the ball comes out to be 44.1 m

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm