Will mark ! 3. jessica stretches her arms out 0.6 m from the center of her body while holding a 2 kg mass in each hand. she then spins around on an ice rink at 1.1 m/s. a. what is the combined angular momentum of the masses? b. if she pulls her arms in to 0.15 m, what is her linear speed if the angular momentum remains constant?

3.

a)

r = distance of each mass in each hand from center = 0.6 m

m = mass of each mass in each hand = 2 kg

v = linear speed = 1.1 m/s

L = combined angular momentum of the masses = ?

Combined angular momentum of the masses is given as

L = 2 m v r

L = 2 (2) (1.1) (0.6)

L = 2.64 kg m²/s

b)

v' = linear speed when she pulls her arms = ?

r' = distance of each mass from center after she pulls her arms = 0.15 m

Using conservation of momentum , angular momentum remains same, hence

L = 2 m v' r'

2.64 = 2 (2) (0.15) v'

v' = 4.4 m/s

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