In case 1, a block hanging on a spring oscillates with amplitude dd. in case 2, an identical block hanging on an identical spring oscillates with amplitude 2d2d. 1) compare the period of the oscillation in case 1 to the period of the oscillation in case 2.

period in case 2 is times the period in case 1

Explanation:

The period of oscillation of a spring is given by:

where

m is the mass hanging on the spring

k is the spring constant

Therefore, in order to compare the period of the two springs, we need to find their m/k ratio.

We know that when a mass hang on a spring, the weight of the mass corresponds to the elastic force that stretches the spring by a certain amplitude A:

So we find

The problem tells us that the amplitude of case 1 is d, while the amplitude in case 2 is 2d. So we can write:

- for case 1:

- for case 2:

And by comparing the two periods, we find:

So, the period of oscillation in case 2 is times the period of oscillation in case 1.

12000j is work done

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.