In a heat engine, if 700 j of heat enters the system, and the piston does 400 j of work, what is the final internal energy of the system if the initial energy is 1,200 j? a 1,100 j b 300 j c 1,500 j d 900 j

Given that

Heat (Q) = 700 J ,

Work (W) = 400 J ,

What is the final  internal energy of the system (u₂) = ?

                                       given  (u₁) = 1200 J

         we know that   ΔU = Q - W  Joules,

                        (U₂ - 1100) = 700 - 400

                                   U₂ = 300 +1100

                                         = 1400 J

The final internal energy is 1400 J

i would think it's food chain

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer