What is the acceleration of a 32-kg object if a 6.75-n force is applied to it? a. 0.21 m/s2 b. 4.74 m/s2 c. 21.09 m/s2 d. 216.00 m/s2

F=MA
*newton 2nd law*
F=6.75N
M=32kg

A= F/M
A=6.75/32
equal
a.0.21m/s2

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