What's the surface temperature of a woodstove with surface area 1.4 m2 that radiates energy at the rate of 18 kw? treat the stove as a blackbody?

Assuming the emissivity is 1.0, the temperature of the wood stove will be about 417 C

Explanation:

You can use the Stefan-Boltzmann formula tying energy with temperature of a blackbody:

P - rate of radiation

is the blackbody's emissivity

is the Stefan-Boltzmann constant

A - area

T - temperature

So,

Assuming the emissivity ( a number between 0 and 1) is 1.0, the temperature of the wood stove will be about 417 C. The emissivity number was not given in your question. If you determine what it is, you can divide this result by the fourth power of that value to get an updated result.

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation:

as a general rule, scissors have blades less than 6 in (15 cm) long and usually have handles with finger holes of the same size. shears have blades scissors used to cut hair or fabric must be much sharper