Car a (1750 kg) is travelling due south and car b (1450 kg) is travelling due east. they reach the same intersection at the same time and collide. the cars lock together and move off at 35.8 km/h[e31.6 s]. what was the velocity of each car before they collided?

Consider the east-west direction along x-axis and north-south direction along y-axis. In unit vector notation, velocities can be given as

= velocity of car A before collision = 0 i - j

= velocity of car B before collision = i + 0 j

= velocity of combination after collision = (35.8 Cos31.6) i - (35.8 Sin31.6) j = 30.5 i - 18.8 j

= mass of car A = 1750 kg

= mass of car B = 1450 kg

Using conservation of momentum

  +   = ( + ) ( )

(1750) (0 i - j) + (1450) ( i + 0 j) = (1750 + 1450) (30.5 i - 18.8 j)

(1450) i - (1750) j = 97600 i - 60160 j

Comparing the coefficient of "i" and "j" both side

(1450) = 97600    and - (1750) = - 60160

= 67.3 km/h        and   = 34.4 km/

1/0.14nm = 10^10/1.4 a lot