Suppose an object in free fall is dropped from a building its starting velocity is 0 m s what is the speed in ms of the object after falling 2 seconds

20m/s

Explanation:

Acceleration is the change in velocity of a body with respect to time. Mathematically;

Acceleration (a) = change in velocity (v-u)/ time taken(t)

Where v = final velocity and u is the initial velocity

a = v-u/t

at = v-u

v = u+at

Since the object is under a free fall, it is acting under the influence of gravity, therefore a = +g(downward fall)

v = u+gt

Given u = 0m/s, g = 10m/s², t = 2seconds

v = 0+10(2)

v = 20m/s

The speed of the object after falling will therefore be 20m/s

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures