Astone is thrown horizontally at 15 m/s from the top of a cliff 40 meters high. how far from the base does the stone hit the ground? pls

She stone hit ground 42.86 m far from base of cliff.

Explanation:

  Initial height from ground = 40 meter.

We have equation of motion , , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this the velocity of body in vertical direction = 0 m/s, acceleration = 9.8 , we need to calculate time when s = 40 meter.

Substituting

So it will take 2.86 seconds to reach ground.

So, stone travels horizontally at 15 m/s for 2.86 seconds.

Distance travelled = 15 x 2.86 = 42.86 m

So, the stone hit ground 42.86 m far from base of cliff.

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