If the velocity of gas molecules is doubled, then it’s kinetic energy will? ( hint formula for kinetic energy is ke=.5 x mv2) a stay the same b double c triple d quadruple

(D) quadruple

Explanation:

-----equation 1

where;

KE₁ is the initial kinetic energy

m is the gas molecule mass

v is the velocity of gas molecules

⇒ When the velocity of gas molecules is doubled (2v)

-------equation 2

Recall; From equation 1;

Substitute in KE₁ in equation 2

KE₂ = 4(KE₁)

Therefore, the kinetic energy will quadruple

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explanation:

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂