Hays is standing outside on a sunny day. he is 6 ft tall and casts a 4 ft shadow. what is the distance from the top of hays's head to the end of his shadow? round to the nearest tenth, if necessary. 4.5 ft 5 ft 7.2 ft 10 ft

Hays' body and his shadow are perpendicular.  

So if you imagine the line from the top of his head to the end of his shadow on the ground, you have a right triangle, and the imaginary line is the hypotenuse.  Then you can stand back and let Dr. Pythagoras figure out the length of the line for you, using c²  =  a² + b²

(Distance)²  =  (Hay's height)² + (length of his shadow)²

(Distance)²  =  (6 ft)² + (4 ft)²

(Distance)²  =  (36 ft²) + (16 ft²)

(Distance)  =  52 ft²

Distance = √(52 ft)²

Distance = 7.21 ft

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