What is the refractive index of a diamond if the angle of refraction in a diamond is 21.10° and the angle of incidence of light from air on the diamond is 60.45°? the refractive index of air is 1.00.

Given data:

Angle of incidence of light (i) = 60.45°,

Angle of refraction of light (r) = 21.10°,,

determine,

                Refractive index of the diamond(n) = ?

Refractive index (n) is the measure of bending of the light ray. It is defined as the ratio of "sine of the angle of incidence (i) to the sine of the angle of refraction(r)". Refractive index is also known as index of refraction.

Mathematically,

                       refractive index (n) = sin i/sin r

                                                       = sin (60.45°) / sin (21.10°)

                                                       = 2.41

The refractive index of the light is 2.41

hèllo, sorry i really need some more points so if you need this qustion answered than retype it

i already answered it by 34/s