As a particle moves 10.0 m along an electric field of strength 75 n/c, its electrical potential energy decreases by 4.8 × 10−16 j. what is the particle's charge? 2. what is the potential difference between the initial and final locations of the particle in problem 1?

a. The charge of the particle is Coulombs.

b. The potential difference between the initial and final locations of the particle in problem 1 is 750 Volts.

Given the following data:

To find the charge of the particle:

The change in electrical potential energy is the work done in moving a charge from one point to another.

Mathematically, the change in electrical potential energy is given by the formula:

Where:

But,

Substituting the given parameters into the above formula, we have;

Charge, q = Coulombs.

2. To find the potential difference between the initial and final locations of the above particle:

Potential difference = 750 Volts

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Part 1)

let say the force on the charge particle which is placed in electric field is given as

now work done to move a charge from one position to other position is known as change in electrostatic potential energy

So here we will have

Part 2)

change in potential energy of charge is product of charge and potential difference between two points

so here we will have

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