A10 kg box initially at rest is pulled 18 meters across a horizontal, frictionless surface by a 40 n force. what is the block’s final velocity over the 18 meters?

The final velocity of the bock over the given distance is 12m/s.

The acceleration of the block is calculated as follows;

F = ma

a = F/m

a = 40/10

a = 4 m/s²

The final velocity of the bock is calculated using the following kinematic equation;

Thus, the final velocity of the bock over the given distance is 12m/s.

Learn more about final velocity here:link

As per work energy theorem we know that

Work done = change in kinetic energy

so here we will have

here we know that

work done is product of force and displacement

now from above equation we have

here we know that

so we will have

so its speed will be 12 m/s

thermal energy is the answer

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west