Your pendulum clock which advances 1.0 s for every complete oscillation of the pendulum is running perfectly on earth at a site where the magnitude of the acceleration due to gravity is 9.80 m/s2. you send the clock to a location on the moon where the magnitude of the acceleration due to gravity is 1.65 m/s2.

As we know that time period of simple pendulum will be

now we will have

time period of a clock on the surface of earth will be 1 s where we have acceleration due to gravity is g = 9.8 m/s/s

now if we took the pendulum to the surface of moon where acceleration due to gravity will be 1.65 m/s/s then this time period will change

so we will say by above equation

now we will have

now plug in all data in this

so time period on moon will be 2.44 s

im srry but ur wrong the answer is d a smooth rock, some red dirt, and an empty bird's nest.