1-3 only. don’t need formula. just work and answer . 10 pts.

1. M1U1 + M2U2 = M1V1 + M2V2

Where M1 is the mass of the first ball, M2 is the Mass of the second ball, U1 is the initial velocity of the first ball, U2 of the second. V1 and V2, the final velocities of the first and second balls respectively.

Substitute the values: (1.5×25) + (2.3×0) = (1.5×0) + (2.3×V2)

37.5 = 2.3V2
V2 = 16.3m/s

2. M1U1 + M2U2 = V(M1 + M2)
Since the collision is elastic, the ball and wood will move with the same velocity

Substitute in the values
(0.005×500) + (5×0) = V(0.005+5)
2.5 = 5.005V
V = 0.499m/s

3. M1U1 + M2U2 = M1V1 + M2V2

Hence; (5×20) + (M2×10) = (5×10) + (M2×15)
100 + 10M2 = 50 + 15M2
50 = 5M2
M2 = 10kg

Please make me Brainliest. I need one more

The duration of a photographic flash is related to an rc time constantly