Aspace vehicle accelerates uniformly from 85 m/s at t = 0 to 164 m/s at t = 10.0 s .how far did it move between t = 2.0 s and t = 6.0 s ?

Explanation:

Given that,

Initial speed of the vehicle, u = 85 m/s

Final speed of the vehicle, v = 164 m/s

Time, t = 10 s

Firstly, we will find the acceleration of the vehicle using first equation of motion as :

Distance covered by the vehicle at t = 2 s is :

Distance covered by the vehicle at t = 6 s is :

So, the distance between t = 2 s to t = 6 s is :

s = 1700 meters

Hence, this is the required solution.

568.98

explanation:

its math

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