Consider a charged parallel-plate capacitor. how can its capacitance be halved?

- doubling k, the permittivity of the dielectric

- doubling A, the area of each plate

- halving d, the distance between the two plates

Explanation:

The capacitance of a charged parallel-plate capacitor is given by:

where

k is the relative permittivity of the dielectric inside the capacitor

is the vacuum permittivity

A is the area of each plate of the capacitor

d is the distance between the two plates

From the formula, we see that we can halve the capacitance by doing any of the following:

- doubling k, the permittivity of the dielectric

- doubling A, the area of each plate

- halving d, the distance between the two plates

increases it

it doesn't. it was imagined up in the middle ages.