An electric motor and a single-fixed pulley work together to lift a 500 kg crate 50.0 m. how much work was done?

a) 10 j
b) 30,000 j
c) 3,000 j
d) 200,000 j

The work done is 245000 J.  

Explanation:  

The formula for the force due to the weight of the object is as follows;

Here, m is the mass of the object and g is the acceleration due to gravity.

Put m=500 kg and g=9.8 meter per second.

The formula for the work done is as follows;

Here, F is the force and s is the displacement.

Put F=4900 N and s=50.0 m.

Therefore, the work done is 245000 J.

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