A0.500 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 40.0 pc charge on its surface. what is the potential near its surface?

We can find the potential using the equation

V = kQ/r

Where V is the potential, k corresponds to the Coulomb constant

k = 9. 10^9 N N. m^2/C^2 ,Q is the charge and r is the radius of the sphere (r = 2.5.10^-3 m)

Substituting in the equation we obtain

V = (9. 10^9 N N. m^2/C^2)*(40.10^-12 C)/(2.5.10^-3 m)  =

V =  144 V (Potential near its surface)

013222

52222222222222222222222222222222222

explanation:

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day