Acharge q of magnitude 6.4 × 10^-19 coulombs moves from point a to point b in an electric field of 6.5 × 10^4 newtons/coulomb. the distance between a and b is 1.2 × 10^-2 meters and the path between a and b is parallel to the field. what is the magnitude of the difference in potential energy?

a. 1.2 × 10^-15 joules
b. 2.3 × 10^-15 joules
c. 3.2 × 10^-15 joules
d. 6.4 × 10^-15 joules
e. 6.4 × 10^-14 joules

Explanation:

The potential difference between point A and point B is given by:

where

is the electric field strength

is the distance between point A and B

Substituting, we find

Now we can calculate the difference in potential energy, which is given by

where

is the charge.

Substituting, we find

probably not the "magnets"in the magnet, so to speak, are thought to be electrons orbiting in shells. vurrent loops two sides to the loop