The motion of a 12kg object is opposed by a 30n force of friction. at what rate does friction slow the object down

The rate at which the friction slows down the object is

Step-by-Step Explanation:

Mass of the object = 12 kg

Opposing Force of friction = F = 30 N

The rate at which the friction slows down the object is actually the deceleration produced by that force.

According to Newton's law:

F = ma

So the acceleration/deceleration produced by a Force F on an object of mass m is a, given by:

a = F/m

Hence deceleration produced by friction = a = 30/12

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.