Aspring with a spring constant of 150 n/m has an equilibrium length of 8.0 cm. what is the change in spring potential energy when the spring is stretched from a length of 11.0 cm to 14.0 cm?

0.20 J

Explanation:

The elastic potential energy stored by a spring is given by:

where

k is the spring constant

x is the length of the compressed/stretched spring

x0 is the equilibrium length of the spring

In this problem, we have:

k = 150 N/m

x0 = 8.0 cm = 0.08 cm

We need to calculate the elastic potential energy in two situations:

- when x = 11.0 cm = 0.11 m:

- when x = 14.0 cm = 0.14 m:

So, the change in elastic potential energy between the two situations is

the answer is horst.

explanation:

in physical geography and geology, a horst is a raised fault block bounded by normal faults. a horst is a raised block of the earth's crust that has lifted, or has remained stationary, while the land on either side has subsided. the word horst in dutch and german means heap – cognate with english "hurst".

i think its