Achild bounces a 57 g superball on the sidewalk. the velocity change of the superball is from 26 m/s downward to 16 m/s upward. if the contact time with the sidewalk is 1 800 s, what is the magnitude of the average force exerted on the superball by the sidewalk? 1. 2183 n 2. 2107 n 3. 1992 n 4. 1877 n 5. 2068 n 6. 1839 n 7. 2030 n 8. 1954 n 9. 2145 n 10. 1915 n

10. 1915 N

Explanation:

The impulse exerted on the ball, I, is equal to the product between the force (F) and the contact time ():

(1)

The impulse is also equal to the change in momentum of the ball, , equal to the product between the mass of the ball (m) and the change in velocity ():

(2)

By merging the two equations (1) and (2) we find:

Solving it for F, we can find the magnitude of the average force:

f=ma newton's second law 7x8=56n

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