If the band is made of a gold alloy with resistivity 6.2×10−8ω⋅m and has a cross-section area 4.5 mm2 , what is the induced current?

In order to find the resistance you need the length of the wire, which you forgot to mention

be subject to a force andchange its motion

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s