Abasketball player can leap upward .65m how long does the basketball player remain in the air use 9.81m/s²

At the player's maximum height, their velocity is 0. Recall that

which tells us the player's initial velocity is

The player's height at time is given by

so we find their airtime to be

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

the correct choice is a .

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