The electric-power industry is interested in finding a way to store electric energy during times of low demand for use during peak-demand times. one way of achieving this goal isto use large inductors. a)what inductance l would be needed to store energy e = 3.0 kwh (kilowatt-hours) in a coil carrying current i = 300a?

240 H

Explanation:

The energy stored in an inductor is given by:

where

L is the inductance of the inductor

I is the current

In this problem, we know:

is the current in the inductor

is the energy stored. We need to convert it into Joules:

So, we can now solve the equation to find L, the inductance:

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