For a satellite to be in a circular orbit 590 km above the surface of the earth, what orbital speed must it be given? express your answer with the appropriate units.

7.57 km/s

Explanation:

The gravitational force on the satellite provides the centripetal force that keeps the satellite in circular orbit, so we can write:

where

G is the gravitational constant

is the Earth's mass

m is the satellite's mass

r = R+h is the distance of the satellite from the Earth's centre, where:

is the Earth's radius,

is the altitude of the satellite above Earth

v is the orbital speed of the satellite

Solving the equation for v, we find

kepler used the data from tycho blahe (his mentor) to construct the laws of planetary motion.

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this