Asimple pendulum consisting of a bob of mass m attached to a string of length l swings with a period t. if the bob's mass is doubled, approximately what will the pendulum's new period be? a: t/2 b: t c: sqrt(2)*t d: 2t if the pendulum is brought on the moon where the gravitational acceleration is about g/6, approximately what will its period now be? a: t/6 b: t/sqrt(6) c: sqrt(6)*t d: 6t if the pendulum is taken into the orbiting space station what will happen to the bob? a: it will continue to oscillate in a vertical plane with the same period. b: it will no longer oscillate because there is no gravity in space. c: it will no longer oscillate because both the pendulum and the point to which it is attached are in free fall. d: it will oscillate much faster with a period that approaches zero

1. B. T

The period of a simple pendulum is given by:

(1)

where

L is the length of the pendulum

g is the gravitational acceleration

From the formula, we notice that the period of the pendulum does not depend on the mass of the bob. Therefore, when the bob's mass is doubled, the period does not change.

2. C: sqrt(6)*T

In this case, the pendulum is brought to the moon, where the gravitational acceleration is

If we substitute this value into the equation for the period (1), we find the new period of the pendulum:

3. B:It will no longer oscillate because there is no gravity in space

Explanation:

The motion (oscillation) of the pendulum is caused by the force of gravity, which "pulls" the bob towards the equilibrium position. If there is no gravity, then there is no force acting on the bob, therefore the pendulum can no longer oscillate.

So, the correct answer is

B:It will no longer oscillate because there is no gravity in space

where is the circuit diagram ?