Ahorse walks along a straight path. it travels 3m in one second 4m in the next second and 5m in the third second. describe the horses motion

The horse is accelerating at a rate of 1m/s^2.

Its velocity is 3m/s in the first second.

It’s velocity is 4m/s in the next second, and 5m/s in the third second.

Since the velocity is increasing at a rate of 1m/s and acceleration is defined as the change in velocity, therefore the acceleration is 1m/s^2.

Let me know if you have any questions.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

snell's law

refractve index = sin incidence / sin refraction