Aferris wheel on a california pier is 27 m high and rotates once every 32 seconds in the counterclockwise direction. when the wheel starts turning, you are at the very top. part awhat is your angular position 75 seconds after the wheel starts turning, measured counterclockwise from the top? express your answer as an angle between 0∘ and 360∘.express your answer in degrees. part bwhat is your speed v?

A) 140 degrees

First of all, we need to find the angular velocity of the Ferris wheel. We know that its period is

T = 32 s

So the angular velocity is

Assuming the wheel is moving at constant angular velocity, we can now calculate the angular displacement with respect to the initial position:

and substituting t = 75 seconds, we find

In degrees, it is

So, the new position is 140 degrees from the initial position at the top.

B) 2.7 m/s

The tangential speed, v, of a point at the egde of the wheel is given by

where we have

r = d/2 = (27 m)/2=13.5 m is the radius of the wheel

Substituting into the equation, we find

no. dot product   =0 when vecs at right angles