Light of wavelength 648.0 nm is incident on a narrow slit. the diffraction pattern is viewed on a screen 57.5 cm from the slit. the distance on the screen between the second order minimum and the central maximum is 1.05 cm . what is the width of the slit in micrometers (μm)?

Explanation:

The formula for the single-slit diffraction is

where

y is the distance of the n-minimum from the centre of the diffraction pattern

D is the distance of the screen from the slit

d is the width of the slit

is the wavelength of the light

In this problem,

, with n=2 (this is the distance of the 2nd-order minimum from the central maximum)

Solving the formula for d, we find:

whichever one it is, it's definitely not one that you included on the list you provided.

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.