A1000kg car has a speed of 32m/s. if it takes 7s to stop the car, what is the impulse and the average force acting in the car

1) Impulse: -32,000 kg m/s

The impulse acting on the car is equal to the change in momentum of the car:

where in this problem we have

m = 1000 kg is the mass of the car

v = 0 m/s is the final velocity of the car

u = 32 m/s is the initial velocity of the car

Substituting values into the equation, we find

2) -4751 N

The impulse exerted on the car is also equal to the product between the average force, F, and the duration of the collision, t:

where in this situation we know

is the impulse

t = 7 s is the duration of the collision

Solving the formula for F, we find the average force:

and the negative sign means that the force is in the opposite direction to the motion of the car.

answer; /// i believe that the correct answer is (c)

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i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!